# Methods of Calculating the A 1 / A 2 Ratio According to Structural Changes ``` release_g7ysit4r6bh5tey5y4z2ieqs7y ```

by Gheorghe Panfiloiu, Gheorghe Panfiloiu

Released as a article-journal .

2018

### Abstract

The paper presents the correlation between the physical model of a dynamic system that is in the steady state dynamic equilibrium and the computer one. The computer model follows the physical model of a dynamic system with one degree of freedom with discretely variable damping. Index Terms-amplitude ratio, computer model, dynamic system, informatic model I. THE PHYSICAL MODEL OF THE DYNAMIC SYSTEM The rheological model used in the analysis is the Voigt-Kelvin model, a model characterized by spring and linear damping in parallel connection with inertial mass and excitation. This model approximates rigorously the interaction between real systems of road structures with earth and vibratory rollers. The amplitude of the motion is given by the relation í µí°´=µí°´= Ω 2 í µí°´íµí°´í µí± í µí±¡ (1 − Ω 2) 2 + 4Ω 2 í µí¼ 2 (1) ie A = A (ω, ζ) is a function expressed in the relative angular coordinate  and the damping fraction ζ. A st or A stable is amplitude in post resonance. The E / V pattern is predominantly elastic, making the chosen layout suitable only for elastic, elastoplastic, low-viscosity landscapes. The Dynamic Stabilized System can be analyzed by analyzing the amplitude evolution relative to the pulse for different discrete damping ratio values. Amplitude and pulsation are two parameters that can be measured during work, so points can be determined on the corresponding curves of evolution. Fig. 1 shows an example of two amplitude-versus-pulse curves for two discretionary damping ratios  and two points p 1 and p 2. In the compaction process, the working points will move from curves with low damping ratios to those with high values. Thus, the instantaneous value of amplitude will be initially on curve 1, corresponding to í µí¼ 1 = 0,175, in point 1. In the compaction process the current point will reach the point marked 2, corresponding to í µí¼ 2 = 0,7, ie on the curve 2.
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